Question
Find the equation of the tangent to the curve $x^{2}+y^{2}+x+y=0$ at $(1,-1)$
Step 1
We can rewrite this equation as $(x+1/2)^{2}+(y+1/2)^{2}=1/4$ which is a circle with center at $(-1/2,-1/2)$ and radius $1/2$. Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 88 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find an equation of the tangent to the given curve at the given point. $$x+2 y+1=\frac{y^{2}}{x-1} \text { at }(2,-1)$$
Differentiation
Implicit Differentiation
Find an equation of the tangent line to the given curve at the specified point. y = x^2 - 1/x^2 + x + 1, (1, 0) y =
Find an equation of the tangent line to the given curve at the specified point. (1, 0) y = (x^2 - 1)/(x^2 + x + 1)
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD