Question
Find the equation of the tangent to the curve $y=(2 x-1) e^{2(1-x)}$ at the point of its maximum.
Step 1
The derivative of the function $y=(2x-1)e^{2(1-x)}$ is given by the product rule and the chain rule. The derivative is given by: \[y' = (2)e^{2(1-x)} + (2x-1)(-2)e^{2(1-x)}\] Show more…
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Level I
The equation of the tangent to the curve $y=$ $(2 x-1) e^{2(1-x)}$ at the point of its maximum is (a) $y=1$ (b) $x=1$ (c) $x+y=1$ (d) $x-y=-1$
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