Question
Find the equation of the tangent to the curve$y=\frac{4}{x^{2}+2}$ at $x=0 .$.
Step 1
Substituting $x=0$ into the equation of the curve, we get $y=\frac{4}{0^{2}+2}=\frac{4}{2}=2$. So the point is $(0,2)$. Show more…
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