Question
Find the equation of the tangent to the curve $y=\sqrt{3 x-2}$ which is parallel to the line $4 x-2 y+5=0$.
Step 1
The derivative of $y$ with respect to $x$ is given by: \[y' = \frac{1}{2\sqrt{3x-2}} \cdot 3 = \frac{3}{2\sqrt{3x-2}}\] Show more…
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