Question
Find the equation of the tangent to the graph of $y=x^{3}-3 x$ at $x=3$
Step 1
We can do this by substituting $x=3$ into the equation $y=x^{3}-3x$: \[y=3^{3}-3(3)=27-9=18.\] So, the point is $(3,18)$. Show more…
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