Question
Find the equations of all lines having slope 0 which are tangent to the curve $y=\frac{1}{x^{2}-2 x+3}$.
Step 1
The derivative of the function is given by: \[y' = \frac{d}{dx} \left(\frac{1}{x^{2}-2 x+3}\right) = -\frac{2x-2}{(x^{2}-2 x+3)^{2}}\] Show more…
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