Question
Find the equation(s) of the tangent line(s) to the graphs of the indicated equations at the point(s) with the given value of $x$.$$x y-x-4=0 ; x=2$$
Step 1
We can substitute x=2 into the equation to find the corresponding y-value. The equation is $xy - x - 4 = 0$. Substituting x=2, we get $2y - 2 - 4 = 0$, which simplifies to $2y = 6$, so $y = 3$. Therefore, the point of tangency is (2,3). Show more…
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