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Find the equations of two lines parallel to $x=2$, and 6 units from it.

$x=8, x=-4$

Algebra

Chapter 1

Functions and their Applications

Section 1

The Line

Functions

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01:43

In mathematics, a function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. An example is the function that relates each real number x to its square x^2. The output of a function f corresponding to an input x is denoted by f(x).

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01:30

Finding Equations of Lines…

01:12

? Finding Equations of Lin…

00:30

Find the equation of the l…

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Find an equation for the l…

01:27

The equations of two lines…

01:06

Use slopes and $y$ -interc…

02:41

Determine whether the line…

for this problem. We have been given an initial line of X equals two. And what we're trying to find is the equation of two lines that are parallel to this given line and that are six units away from it. Okay, so parallel lines that air six units away. So let's start by graphing that original line X equals two. Well, X equals two. I'm going to come out and put two on my X axis. There is no why in this equation, which means that the white corn it doesn't matter as long as X is too I could have. Why be any value I want? So as you can see, this is if I was using a ruler. Pencil on paper will be a lot straighter, but this is a vertical line. X equals to the Y. Coordinate could be whatever we want it to be. So if I want to be parallel to this, I'm going to still continue tohave vertical lines. So my two answers are going to be X equals because vertical lines always have an X and know why that that's how we could recognize vertical lines. If I'm six units away, I could go one of two directions. I could go six units to the right. That puts me over here in X equals eight. Oh, that's a very not straight line. It's supposed. We're gonna pretend that that is perfectly vertical, even though it it went a little wonky there. But that Linus, 60 minutes away from my blue line, that's it. X equals eight. If I go 16, it's to the left of my blue line. That puts me over here. It X equals negative four. That's a little bit straighter. So either one of these lines is six units away from my original blue line parallel to it.

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