Question
Find the equilibrium solutions and determine which are stable and which are unstable.$$y^{\prime}=e^{-y}-1$$
Step 1
Equilibrium solutions are the solutions where the derivative of the function is zero. So, we set the derivative equal to zero and solve for $y$: $$y^{\prime}=e^{-y}-1=0$$ Show more…
Show all steps
Your feedback will help us improve your experience
Victoria Dollar and 57 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the equilibrium solutions and determine which are stable and which are unstable. $$y^{\prime}=y^{3}-1$$
First-Order Differential Equations
Direction Fields and Eulers Method
Find the equilibrium solutions and determine which are stable and which are unstable. $$y^{\prime}=y^{2}-y^{4}$$
Find the equilibrium solutions and determine which are stable and which are unstable. $$y^{\prime}=2 y-y^{2}$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD