Question
Find the exact arc length of the curve over the interval.$$x=\frac{1}{8} y^{4}+\frac{1}{4} y^{-2} \text { from } y=1 \text { to } y=4$$
Step 1
The derivative of $x$ with respect to $y$ is given by: $$ \frac{dx}{dy}=\frac{d}{dy}\left(\frac{1}{8} y^{4}+\frac{1}{4} y^{-2}\right)=\frac{1}{2} y^{3}-\frac{1}{2} y^{-3} $$ Show more…
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