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Find the exact length of the curve. $ y = \fra…

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Problem 16 Easy Difficulty

Find the exact length of the curve.

$ y = 3 + \frac{1}{2} \cosh 2x $ , $ 0 \le x \le 1 $


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Related Courses

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 8

Further Applications of Integration

Section 1

Arc Length

Related Topics

Applications of Integration

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Watch More Solved Questions in Chapter 8

Problem 1
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Problem 5
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Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
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Problem 32
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Problem 34
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Problem 36
Problem 37
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Problem 45
Problem 46

Video Transcript

ants Claressa when you raid here. So we're gonna find the curve length of the curve. So we get the Y over DX to be signed two x, and we're going to square both sides and add one to the expression. So when we do that, we get one plus d y over tea cups square, it goes one plus square two x is equal to And when we recall the identity the hyperbolic sign and coast on eternity we get gosh square of two months. Don't we square? Root the expression? No. We're gonna integrate from 0 to 1. Caution two X t x. This becomes equal to one. Have a sign. I probably like function of two x from 0 to 1. This is equal to e square minus eat the negative two over for

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