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Find the exact value of each expression (without acalculator.)$$\begin{array}{l}{\text { (a) } \log _{2} 6-\log _{2} 15+\log _{2} 20} \\ {\text { (b) } \log _{3} 100-\log _{3} 18-\log _{3} 50}\end{array}$$
a) 3b) - 2
Calculus 1 / AB
Chapter 3
INVERSE FUNCTIONS
Section 2
Inverse Functions and Logarithms
Derivatives
Differentiation
Applications of the Derivative
Harvey Mudd College
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specialist, every compressing this into a single law. Opportunities to weaken usar quotient rule trust laws. Two of 6/15 and then we have plus laws based two of 20 are now using our product. Oral or create making are some into a product we get log. There's two of 20 times six and then divided by 20 or divided by 15. That's equal to eight To have log to its left. Texas equal to y. And now let's rewrite this as an exponential function. That is, we have Susan. Careful. I say on a is to the power of three. So by our uniqueness, probably we have that y is equal to three. Okay, so now for part B will do the same thing. So since we have the difference, we can use a Kocian role. Now we want to use our quotient rule one more time. That's log three of 100 times 50 divided by 18. Um, that's 5000 over 18. So far. 1000 over 18. Um, what do we have? Oh, actually, sorry. That's wrong. We're using the potion roll. That's one whole 100 over 18 times with Okay, So what does that give us the laws. These three of 100 over 1850 50? Um, we get 900. That's equal to one over night when we can you write this as log is 333 power of date of two. And that gives us negative, too.
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