00:01
In this problem we have given tangent theta is equal to 1 where theta is greater than minus 180 degree and smaller than minus 90 degrees.
00:17
And we are asked to find the value of sine theta upon 2, cosine theta upon 2 and tangent upon 2.
00:26
So first of all we will find the value of cosine theta.
00:31
By using the trigonometric identities, we know that cosine theta is equal to minus.
00:38
1 upon under root 1 plus tangent square theta.
00:44
By substituting the value of tangent theta we get cosine theta is equals to minus 1 upon under root 2.
00:52
Now we will find the value of sine theta upon 2 and we know that theta upon 2 lies in the 4th quadrant so we have sine theta upon 2 is equal to minus under root 1 minus cosine theta upon 2.
01:10
Now we will substitute the value of of cosine theta we get minus under root 1 plus 1 upon under root 2 upon 2.
01:22
By simplifying it we get sine theta upon 2 is equals to minus under root 2 plus under root 2 2 upon 2.
01:38
Therefore we get sine theta upon 2 is equals to minus under root 2 plus under root 2 upon 2...