00:01
We have a function, and we are trying to figure out where we have extrema, both local and absolute.
00:07
First, we look at this function.
00:09
It looks like there could be a possibility that the denominator would be zero at some point, which would indicate that we have a point that can't be plotted.
00:20
However, we should notice that that doesn't factor.
00:24
And if we run the discriminant test on it, which is to figure the value of b squared minus 4ac, we find that that discriminant is negative.
00:34
And if the discriminant is negative, then indicates that the quadratic formula is not going to yield any solutions.
00:43
Now, let's determine the critical points.
00:48
We can find that by taking the bottom, the derivative at least, the bottom times the derivative of the top, which is one, minus the top, times the derivative of the bottom, which is 2x plus 2, and put that over the bottom squared.
01:12
Okay, so let's simplify that top.
01:14
We're going to have x squared plus 2x plus 2.
01:20
If we foil x plus 1 times 2x plus 2, we would have 2x squared.
01:28
Middle terms of 2x and 2x, so that's plus 4x, and then 1 times 2 to get 2.
01:40
Let's go ahead and simplify that top.
01:47
We will distribute the negative that's on top.
01:55
This or the top here.
02:03
Negative x squared minus 2x, and then the plus 2 minus 2 cancels.
02:16
Now, where are critical numbers? well, the derivative would be 0 if the top is 0.
02:24
So there could be a critical number there if negative x squared minus 2x is equal to zero.
02:32
Pull out an x.
02:33
Well, actually pull out a negative x.
02:35
That would leave x plus two, yielding solutions of x equals zero and negative two for our critical numbers.
02:46
Now, those are both horizontal tangent points.
02:51
So let's fill them in.
02:53
Whoops...