00:01
We are looking for absolute and local extrema for this function.
00:05
Domain is all x values because you can take e to any value.
00:10
Let's find the critical numbers.
00:13
Our derivative is e to the x minus e to the negative x, which is equivalent to e to the x minus one over e to the x.
00:26
Function is never non -differentiable because e to the x that's in this denominator can never be zero.
00:33
So the only critical numbers we could have would be when the derivative is equal to zero.
00:42
To solve this, i will add the 1 over e to the x to both sides.
00:50
I will then multiply both sides by e to the x.
00:54
And if i multiply e to the x times e to the x, that's e to the 2x.
01:00
So i have e to the 2x equals 1.
01:06
Well, when is that true? e to the 0 is 1, which means 2x is 0, therefore x is 0.
01:19
So that's our critical point.
01:20
And it's our only critical point.
01:25
If x is 0, then y would be e to the 0 plus e to the 0...