00:01
We are looking for extrema for this function.
00:04
And first, let's make the statement that x has to be greater than zero, because we can only take the natural log of positive values.
00:13
Let's find the critical points by taking the derivative.
00:17
Use the product rule.
00:19
First times the derivative of the second plus the second times the derivative of the first, which is one.
00:28
So we have 1 plus natural log x.
00:34
Now, it would be non -differential for values zero and below, but we already know that's not in the domain.
00:41
So the critical numbers we're looking for are when the derivative is zero.
00:49
Subtract the one.
00:54
Okay, so what does this mean? what's the value of x? well, we can rewrite that as e to the l in x equals e to the negative first.
01:04
And we would do that because we know that e to the l and x is x.
01:09
So we end up with a value of x equals 1 divided by e...