00:01
Suppose we have a sequence where the first term, a1, is the square root of 2, and the common ratio r is also the square root of 2.
00:08
Let's determine the fifth term in this sequence.
00:11
Well, there's two different ways to do this with a formula or by brute force.
00:15
Now, since we're going to be finding the nth term later using the formula, i'll illustrate the brute force method here to find the fifth term.
00:23
That is, we have the first term, the square of two, and then the second term will just be the first term, multiplied by the common ratio.
00:31
So that is square of two times squared of two, which just gives us two, or square root of two squared.
00:38
All right, now the next term will be that multiplied by the constant ratio, or common ratio rather, giving us two squared of two.
00:45
Then after that we multiply by another square root of two, giving us two times the square root of two squared, or just two times two, which is four.
00:55
And finally, the fifth term multiplies that by another square root of two, giving us 4 times the square root of 2.
01:02
So the fifth term is 4 times the square root of 2.
01:06
Now let's move on to the nth term...