00:01
Okay, in this question, f -dash -x is given 3x squared divided by 2 square root of x -q minus 1, and one more information is given that our function passes through 1 .1.
00:14
It means f -1 equals to 1.
00:17
So first of all, we have to find out function fx, and function fx can be written as integration of f -d -x, okay? so, fx will be integration of value of f -dash -x that is given here.
00:33
It is 3x squared divided by 2 square root of x -cube minus 1 and dx.
00:40
It means we have to solve this integration.
00:43
So for this, we will substitute u equals to x -cube minus 1.
00:47
So du will be 3x square dx and 3x square dx is present in our numerator.
00:53
So it will be integration and 3x2.
00:56
X squared d x numerator it will be d u divided by two and square root of x q minus 1 that is u now we will take 1 by 2 outside integration and 1 by square root u that can be written as u raised to the power minus half and d u and now 1 by 2 integration of u raised to the power minus half it will be u raised to the power minus half plus 1 that is plus half divided by 1 by 2 or we can say multiply by 2 okay plus constant c so this is the value of function now we will simplifying it this 2 will be cut out this 2 and it will be u raised to the power half or we can say root u plus c okay so this will be our function and one more information is given that is our function passes through 1 comma 1 so we can say the value of f 1 is given 1.
01:49
Okay...