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Problem 46 Medium Difficulty

Find the first and second derivatives of the function.
$ G(r) = \sqrt{r} + \sqrt[3]{r} $

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Video Transcript

he It's clear. So when you read here so we have our original function. G a r. She's equal to our The one have plus our two the 1/3. And then we're going to apply to some and par ral to differentiate. We get 1/2 our it's a negative one house close 1/3 are than negative 2/3. And for the second derivative, we're gonna different sheet. The first derivative, we're gonna apply to some and constant part multiple rule and differentiate the rest using the power off. So I get half negative, half hard to the negative three house plus 1/3 negative 2/3 are too negative. 5/3. This is equal to negative 1/4 hard to the negative three house plus negative to ninth are to the negative 5/3