We do this by substituting the values of n from 1 to 4 into the given formula $a_{n}=3 n-10$.
For $n=1$, $a_{1}=3(1)-10=-7$.
For $n=2$, $a_{2}=3(2)-10=-4$.
For $n=3$, $a_{3}=3(3)-10=-1$.
For $n=4$, $a_{4}=3(4)-10=2$.
So, the first four terms of the sequence
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