The norm of a vector $\mathbf{u}=\langle u_1, u_2\rangle$ is given by $\|\mathbf{u}\|=\sqrt{u_1^2+u_2^2}$. So, for $\mathbf{u}=\langle 1, \frac{1}{2}\rangle$, we have $\|\mathbf{u}\|=\sqrt{1^2+\left(\frac{1}{2}\right)^2}=\frac{\sqrt{5}}{2}$.
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