00:01
Okay, so we'll start by using our difference rule to split up our integral into two integrals.
00:06
So we get the following.
00:14
Okay, and now let's notice that we have constants in front of our e and our 9.
00:18
So we can use our constant multiple rule to bring that outside.
00:28
Okay, and now let's use our, or let's solve our integral.
00:33
So 1 over x, the integral of that, well, that's equal to ln of the absolute value of x, minus 3, and then the integral of exponential, that's e to the power of negative 0 .4x, over that constant, which is negative 0 .4...