00:01
For this problem, we are asked to find the function f, given the slope of the tangent line, f prime, at the point x, f of x, f of x, and that the graph of f passed through the given point.
00:11
So we're given that f prime of x equals one half, x power of negative, one half, and it passes through the point to root 2.
00:17
So to begin, we want to find the antiderivative of our given f prime.
00:23
So we know that the anti -derivative for something in the form of a power, it's going to be, so in this case, it's going to be x the power of negative one -half plus one, divided by negative one -half plus one.
00:37
So negative one -half plus one is going to give us just positive one -half.
00:41
So we have positive one -half as the exponent on x and we divide by negative one -half, which is going to be the same thing as multiplying by two up top, which will cancel out with the one -half out front...