Question
Find the function $f$ such that $$f ^ { \prime } ( x ) = f ( x ) ( 1 - f ( x ) )$ and$f ( 0 ) = \frac { 1 } { 2 } .$$
Step 1
Step 1: First, we rewrite the given differential equation $f ^ { \prime } ( x ) = f ( x ) ( 1 - f ( x ) )$ in terms of $y$ and $dy/dx$ as $dy/dx = y(1-y)$. Show more…
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Find the function $f$ such that $f ^ { \prime } ( x ) = f ( x ) [ 1 - f ( x ) ]$ and $f ( 0 ) = \frac { 1 } { 2 } .$
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$$\begin{array}{l}{\text { Find the function } f \text { such that } f^{\prime}(x)=f(x)(1-f(x)) \text { and }} \\ {f(0)=\frac{1}{2} .}\end{array}$$
Find the function $f$ such that $f^{\prime}(x)=f(x)(1-f(x))$ and $f(0)=\frac{1}{2} .$
APPLICATIONS OF INTEGRATION
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