The derivative of $h(\theta)$ is given by the power rule, which states that the derivative of $x^n$ is $nx^{n-1}$. So, the derivative of $h(\theta)$ is:
$$h'(\theta) = 2 \cdot \frac{3}{3} \cdot \theta^{\frac{2}{3} - 1} = 2 \cdot \theta^{-\frac{1}{3}}.$$
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