00:01
In this problem, we have been given two functions, f of x and g of x.
00:04
Now, first of all, we need to determine f plus g.
00:08
By definition, f plus g of x is equal to f of x plus g of x.
00:14
Now, f of x is given to be equal to 1 divided by x square plus 1, and g of x is given to be equal to 1 divided by x square minus 1.
00:24
If we add these two terms, in the denominator we have the lcm, which is x squared, square plus 1 times x square minus 1.
00:33
In the numerator, we will have x square minus 1 plus x square plus 1.
00:40
So in the numerator, we can see that the minus 1 and the plus 1 will get canceled out, and we'll be left with 2x square.
00:46
And then in the denominator, we have x square plus 1 times x square minus 1.
00:50
That is x square whole square, which is x22 power 4, minus 1 square, which is minus 1.
00:56
Hence the expression for f plus g of x is 2x squared divided by x to the power 4 minus 1.
01:03
Next we have to determine f minus g by definition f minus g of x is equal to f of x minus g of x minus g of x.
01:13
So this will be 1 by x square plus 1 minus 1.
01:17
Minus 1.
01:20
If we take the lcm in the denominator we have x square plus 1 times x square minus 1...