00:01
Dear students, here we have second order non -homogeneous differential equation and we have to find the general solution.
00:08
If you look at our differential equation here, we've got non -constant coefficients.
00:20
So these are non -constant coefficients.
00:23
So we can name these type of differential equations as koshu -elogy equation.
00:28
So we'll let x equals to e to the power t and by taking ln on both side we'll get t equals to ln of x and we differentiate t with respect to x we'll get one upon x so now we can just shift our variable of x in terms of t so that we will eliminate the non constant coefficients we know that d y upon d x is equal to so by chain rule method you can just multiply and divide by t so we'll that d -y upon d -t into d -t upon d -x.
01:08
So we know that d -t upon d -x is 1 upon x, so we'll put 1 upon x of d -y upon d -t.
01:17
Then we'll take the second derivation with respect to x, which will give us, this is our first term, this is our second term, so we'll apply the product rule of differentiation...