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Hi there.
00:01
So for this problem, we are asked to find the general solution to laplace equation in spherical coordinates.
00:11
For the case where the potential difference depends only on the radial coordinate.
00:17
So do the same for cylindrical coordinates, assuming also that the potential difference depends only on x.
00:28
So in here, we start with the laplace equation in its vertical coordinates.
00:37
So for a potential that depends only on the radial coordinate, so we will have that this is.
00:48
So this is the laplacean, laplaceian or laplace operator.
00:54
And this applied to the potential is equal to 1 over the radius square times the derivative with respect to the radius and this applied to the product between the radius square and the derivative of the potential with respect to the radius and we set this equal to zero.
01:15
So in here, because we know that this is equal to zero, we know that this, this product inside the derivative should be a constant.
01:27
So setting that as a constant, we're going to call that constant just c and then what we can do in here is to is to separate the variables we can pass the radius to the other side so we will have the following we'll have c divided by the radius square then if we integrate this both sides of this expression we'll find the potential and we know that the integral the integral of 1 over the radius square is minus 1 over the radius...