Question
Find the given quantities. The error function, erf $(x),$ is defined by \[\operatorname{erf}(x)=\frac{2}{\sqrt{\pi}} \int_{0}^{x} e^{-t^{2}} d t.\]$$\frac{d}{d x}\left(\int_{x}^{x^{3}} e^{-t^{2}} d t\right)$$
Step 1
\] In this case, our function is $e^{-t^{2}}$ and our interval is from x to $x^{3}$. So, we have \[\int_{x}^{x^{3}} e^{-t^{2}} dt = F(x^{3}) - F(x).\] Show more…
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