00:01
Okay, so we are to take the gradient of the function, and the gradient is just the vector whose components are the partial derivatives of the inputs.
00:09
In this case, there are three inputs.
00:12
So we're going to need three components because we're going to have three partial derivatives with respect to x, with respect to y and with respect to z.
00:20
Now, you might notice that this function is very, very symmetric, right? in fact, in polar coordinates, this is simply just r, simply the radial distance.
00:31
So that being said, we only really need to find one of the partial derivatives because the other two are going to be very, very similar.
00:40
You're just going to replace x with y, y with c, et cetera.
00:43
So that makes this problem a lot easier.
00:45
So always look for symmetry in these kinds of questions.
00:49
So like i said, we're going to take the partial with respect to x of this function...