00:01
Here in this question we have given that f of x, y, z is equal to cos inverse z divided by square root of x square plus y square plus z square.
00:19
And we have to find out the value of gradient f of x, y, y, z, that is grad of, f x y z since we know that grad of f x y z is equals to f x of x y z f y of x y z and f z of x y z say this is our equation then we need to find out the value of f x x y z similarly f x y z of x y z similarly fy and fz.
01:02
So, fx, x, y, z is equal to dabor f over dabor x, that is partial differentiation of f with respect to x treating y, z as a constant.
01:16
So from here we'll get minus 1 divided by square root of 1 minus z square over x square plus y square plus z squared that is square of square root x square plus y square plus z square and in the numerator part we'll get z multiplied by minus 1 by 2 x square plus y square plus z square plus x square plus z square rhti power minus 3 by 2 multiplied by 2 x now by solid involving this, we will get fx of x, y, z as xx divided by x squared plus y square plus z squared plus z squared multiplied by square root of x square plus y square.
02:22
This is the value of fx.
02:24
Now similarly we can find the value...
