To find the indefinite integral of $(2t+1)(t-2)$, we can use the distributive property to expand the expression:
$(2t+1)(t-2) = 2t(t-2) + 1(t-2)$
Now we can simplify each term separately:
$2t(t-2) = 2t^2 - 4t$
$1(t-2) = t - 2$
Now we can integrate each term
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