3 t^{2}+0.02 t+2\right) d t = 0.3\int t^{2} dt + 0.02\int t dt + 2\int dt$$
Now, we can find the indefinite integral for each term:
1) For the first term, we have:
$$0.3\int t^{2} dt = 0.3\cdot\frac{1}{3}t^3 + C_1 = 0.1t^3 + C_1$$
2) For the second term, we
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