In this case, $n=3$, so we have:
$$\int 6x^3 dx = 6\frac{x^{3+1}}{3+1} + C = \frac{6x^4}{4} + C = \frac{3x^4}{2} + C_1$$
2) For the second term, $\int \frac{3}{x^2} dx$, we can rewrite the integrand as $3x^{-2}$ and then apply the power rule again:
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