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Find the indicated velocities and accelerations.A person on a hoverboard is riding up a ramp and follows a path described by $y=0.15 x^{1.2} .$ If $v_{x}$ is constant at $0.50 \mathrm{m} / \mathrm{s},$ find $v_{y}$ when $x=8$.

Calculus 1 / AB

Chapter 24

Applications of the Derivative

Section 3

Curvilinear Motion

Derivatives

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here. We're going to apply equation to 11 and here we can say that Ah, the velocity of the wind direction is equaling zero at Why equaling? Why, Max? So we can then say that zero equaling the initial velocity of 12 meters per second plus negative 2.0 meters per second squared, multiplied by T tease, then giving us 6.0 seconds. So to find the velocity in the X direction at 6.0 seconds, this would be equaling the initial X velocity of eight meters per second. Plus the acceleration in the ex direction 4.0 meters per second squared multiplied by 6.0 seconds. And this is giving us 32 meters per second. So we can then say that at why equaling? Why, Max, we can say that the velocity and the ex direction in this case, the velocity vector would be equaling 32 meters per second I hat. So we should actually just say that this would be our final answer. That is the end of the solution. Thank you for watching

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