00:03
I am the given caution we're given fx with a given domain.
00:08
We need to find out the inverse function and then we need to state its domain.
00:16
So if we just go with that, we're given fx is equal to x square minus 1.
00:23
So fx equals x square minus 1, all divided by x square plus 1, x2 plus 1, right? in the domain, for this function is given as x is less than equal to 0.
00:42
Now to find the inverse function, what we'll do, we'll put y equals x square minus 1 over x squared plus 1.
00:50
Next step we'll do, we just replace x and y, so we get x equal to y square minus 1 over y square plus 1, and then find the value y from here, so we get x y square plus x equals y square minus 1.
01:05
So we saw this, we get x minus 1, y square equals, we get from the, we get from here minus x minus 1 or we get y squared equals minus x minus 1 over x minus 1 or we get x plus 1 over 1 minus x right multiplying the numerator denominator with minus 1 so uh now we have here for the negative domain x is less than equal to 0 right so this is domain here and that domain become the range so y value is coming out to be we did the negative value now here not positive values it will be negative root x plus 1 over 1 minus x this is we get the inverse function so we get f inverse x is coming out to be so f inverse x is equal to we will have minus square root x plus 1 over 1 minus x that's coming hard to be the inverse function now to find domain of this so domain is we have this one square root that means this part here and that a square root that should be greater than equal to 0.
02:17
So we have x plus 1 over 1 minus x that should be greater than equal to 0.
02:23
So from here you find out domain.
02:26
So we draw here sign diagram.
02:31
So we have x equal to 1...