00:01
Okay, so for this question, we're to ask to find the inverse of a 3x3 matrix here.
00:06
We'll call it a.
00:07
I'm proposing that we use this formula that says that a inverse is equal to 1 over the determinant of a times the adjunct of a.
00:24
So how we're going to find the determinant is by the method of picking a number from a row.
00:34
We're going to use the top row here, but you can actually use this method for any row.
00:38
And so we're going to pick 0, and then we're going to get the remaining.
00:45
If we take out the row and column that 0 is in, and we find the determinant of the remaining matrix and multiply it by 0, we're going to use that portion.
00:52
So the determinant of the remaining here would be 5 minus 2, 5 minus 4 rather, but it's multiplied by 0, so it doesn't matter.
01:00
Then we subtract off 1 times 3 minus 2.
01:09
And then again, we're going to have plus 0, eliminate the row and columns.
01:14
The determinant of this matrix is going to be 6 minus 5.
01:23
And in the end, the only thing that actually stays is this middle term.
01:27
And so we get that the determinant is minus 1.
01:30
So 1 over minus 1 is just going to be minus 1.
01:34
So then we need to find out what this matrix.
01:40
Is.
01:46
And the way that we're going to do that is through a kind of convoluted method.
01:50
So we're going to write out this whole matrix.
01:53
0 .10 .352.
01:58
1, 2.
01:59
And we're going to copy down the first two columns onto the right side of it...