Question
Find the kinetic energy of a $78.0-\mathrm{kg}$ spacecraft launched out of the solar system with speed $106 \mathrm{km} / \mathrm{s}$ by using (a) the classical equation $K=\frac{1}{2} m u^{2}$. (b) What If? Calculate its kinetic energy using the relativistic equation.
Step 1
The mass $m$ is given as $78.0 \, \mathrm{kg}$ and the speed $u$ is given as $106 \, \mathrm{km/s}$ which is equal to $1.06 \times 10^{5} \, \mathrm{m/s}$. Show more…
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Find the kinetic energy of a $78.0-\mathrm{kg}$ spacecraft launched out of the Solar System with a speed of $106 \mathrm{~km} / \mathrm{s}$ using (a) the classical equation $K=\frac{1}{2} m v^{2}$ and (b) the relativistic equation.
(a) Find the kinetic energy of a 78.0-kg spacecraft launched out of the solar system with speed 106 $\mathrm{km} / \mathrm{s}$ by using the classical equation $K=\frac{1}{2} m u^{2} .$ (b) What If? Calculate its kinetic energy using the relativistic equation. (c) Explain the result of comparing the answers of parts (a) and (b).
Calculate the kinetic energy (where the kinetic energy of a moving body is given by: KE = 1/2(mv^2), with the appropriate units) of the Earth as it moves through space in orbit around the Sun. The mass of the Earth is about 6 x 10^24 kg and during one trip around the Sun the Earth will have traveled about 9.42 x 10^8 km. Express your answer in scientific notation to two decimal places using the format 1.23e45 or 1.23e-45. Answer in Joules.
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