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Find the kinetic energy of an electron whose de Broglie wavelength is 2.5 $\mathrm{A} .$

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Physics 103

Chapter 30

Quantum Physics

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McMaster University

Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

02:50

Calculate the de Broglie w…

01:09

What is the de Broglie wav…

02:42

What is the kinetic energy…

03:15

$\bullet$ Find the wavelen…

02:30

Find the wavelengths of a …

03:18

07:54

(a) Find the kinetic energ…

03:10

Find the de Broglie wavele…

02:43

An electron and a photon e…

02:17

well, kinetic energy equals Ah, Peace Square, divided by two m peas. The momentum and we know that momentum equals Oh, it's divided by Linda. Momentum equals H divided lander Edge is 6.63 Multiply by 10 to the power minus 34 jewels second, divided by rebel in't, that length is 2.5, multiplied by 10 to the minus 10 meters and dividing the two numbers. Momentum is equal to, uh, 2.65 to multiply by 10 to the power minus 24 uh, kilogram mater per second and peace where piece where equals, um 7.0 7.0 multiplied by 10 to the power minus 48 uh, kilogram mater or second. Now let's calculate a kinetic energy, since kinetic energy is it called p squared divided by two m. Let's put the value off the square in kinetic energy creation, so kinetic energy equals 7.0. Multiply by 10 to the power minus 48 minus 48 divided by two times moss and moss equals, uh, 9.1 month of my return to the bar minus 31. It's the mass of electrons. Therefore, kinetic energy, eyes equal to, um, 0.38 point tree. It multiply by, um, 10 to the power minus 17 jewels minus 17 Jewels and further skinned originates. 3.8 multiplied by 10 to the power minus. That's 70 minus 17. So three pointed multiplied A tentative are minus 18. Here we have minus 18 Jew.

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