Question
Find the LCD for the fractions in each list.$$\frac{6}{a^{2}+6 a}, \frac{-5}{a^{2}+3 a-18}$$
Step 1
For the first fraction, the denominator is $a^{2}+6a$. We can factor out an $a$ from this expression to get $a(a+6)$. For the second fraction, the denominator is $a^{2}+3a-18$. We can factorize this expression into $(a-3)(a+6)$. Show more…
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