Question
Find the length of a simple pendulum that has a period of $2.00 \mathrm{~s}$. Assume $g=9.81 \mathrm{~m} / \mathrm{s}^{2}$.
Step 1
We know the formula for the period of a simple pendulum is given by: T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Show more…
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Find the length of a simple pendulum that has a period of 1.00 s. Assume that the acceleration of gravity is $g=9.81 \mathrm{m} / \mathrm{s}^{2}$
Find the length of a simple pendulum that has a period of 1.00 s. Assume that the acceleration of gravity is $g=9.81 \mathrm{m} / \mathrm{s}^{2}$.
Find the legnth of a simple pendulum whose period is $1.00 \mathrm{~s}$ at a location where $g=9.82 \mathrm{~m} / \mathrm{s}^{2}$
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