00:01
In the problem, we have the length of curve is given as a's, that is, integration 0 to 3, root over of 1 plus, d .y upon d x, whole square, dx.
00:23
Now here as y is equal to root over of a minus x.
00:29
So we have dy over dx, that is equal to 1 upon 2, root over of, that is, here it is, sorry, this is 9 minus x square or it is root over of 9 minus x square.
00:54
So it becomes 9 minus x square into minus 2x.
01:09
These two can says this two, therefore it is equal to minus x over root over of 9 minus x square.
01:18
Now we have d .y over dx as this...