Question
Find the lengths of the curves.$$x=\int_{0}^{y} \sqrt{\sec ^{4} t-1} d t, \quad-\pi / 4 \leq y \leq \pi / 4$$
Step 1
The derivative of an integral from a constant to a variable is just the function evaluated at that variable. So, we have: \[x'(y) = \sqrt{\sec^{4}y - 1}\] Show more…
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