Question
Find the lengths of the curves.$$y=\frac{x^{3}}{3}+\frac{1}{4 x}, \quad 1 \leq x \leq 3$$
Step 1
The function is $f(x) = \frac{x^{3}}{3}+\frac{1}{4x}$. The derivative of this function is $f'(x) = x^{2}-\frac{1}{4x^{2}}$. Show more…
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