00:01
In this problem, we need to apply a l -opetals rule in order to determine a given limit.
00:05
Now, let us consider y to be equal to 1 minus 3 by x to the power x, because we need to determine the limit as x tends to infinity of this expression.
00:18
So let us take the natural logarithm on both sides.
00:20
So we have that lawn -y is equal to lawn of this expression.
00:23
And using the power rule of logarithms, this will be equal to x times loan of 1 minus 3 by x.
00:32
So we can consider the limit in this case.
00:38
That is consider the limit as x tends to plus infinity of y.
00:44
Then that will be equal to the limit as x tends to plus infinity of x times lawn of 1 minus.
00:54
3 by x.
00:56
Now note that on the right hand side we have x tends to infinities and then we have lawn of 1 minus 3 by x as x tends to infinity that will be 1 minus 0.
01:06
So just 1 and lawn of 1 is 0.
01:09
So we have an infinity time 0 form and we cannot apply a law.
01:12
It is rule like this.
01:14
So we rewrite this as limit x tends to plus infinity of lawn of 1 minus 3 by x divided by 1 divided by x.
01:22
Then the numerator will tend to 0 and the denominator will also tend to 0 as x tends to plus infinity and we have a 0 by 0 form and thus we can apply l hoppetals rule.
01:33
So applying l hoppetals rule, we take the derivative of the numerator.
01:38
So that will be 1 divided by 1 minus 3 by x times the derivative of 1 minus 3 by x.
01:44
So that will be 0 minus 3 times minus 1 by x square.
01:49
And in the denominator, we have the derivative of 1 by x.
01:53
So that will be minus 1 by x squared...