SOLVED:Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why. \lim_{x\to 1} \frac{x\sin(x - 1)}{2x^2 - x

Name: find the limit use lhospitals rule where appropriate if there is a more elementary method conside 29
Uploaded: 2021-05-27
Duration: 1 min 9 s
Channel: Numerade
Description: Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why. $ \lim_{x\to 1} \frac{x\sin(x - 1)}{2x^2 - x - 1} $