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# Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why.$\displaystyle \lim_{x\to \infty} \left( \frac{2x - 3}{2x + 5} \right)^{2x + 1}$

## $e^{-8}$

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##### Kristen K.

University of Michigan - Ann Arbor

##### Samuel H.

University of Nottingham

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### Video Transcript

So this problem we're going to be taking the natural log of both sides to start. And that will allow us to put it in a simpler form. That's going to be the natural log of two X -3. Um Natural log of two x -3 Over two X Plus five. And that is all gonna be over one divided by two x plus one. When we plug in X equals infinity. We get 0/0 which is the indeterminate form. Um So we're gonna use local towels role. Then using that we're able to end up getting negative uh negative eight times choo X Over X. Class one over X. Weird. And then on the denominator were able to get choo X over X Plus five over acts times two. X. Overact -3 over X. And the reason we do this is so that way when we evaluate it to infinity a lot of these things go to zero. Just leaving us with a -8. So since this is the natural log of Y equals negative eight. Our final answer is going to be Y equals E. To the negative age

California Baptist University

#### Topics

Derivatives

Differentiation

Volume

##### Kristen K.

University of Michigan - Ann Arbor

##### Samuel H.

University of Nottingham

Lectures

Join Bootcamp