Question
Find the limits.\begin{equation}\lim _{x \rightarrow 0} \frac{1-\cos 3 x}{2 x}\end{equation}
Step 1
This gives us: \begin{equation} \lim _{x \rightarrow 0} \frac{1-\cos 3 x}{2 x} = \lim _{x \rightarrow 0} \frac{\sin^2 3x}{2 x} \end{equation} Show more…
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