Question
Find the limits.$f(x)=4-x^{2}, g(x)=\sqrt{x+1}$(a) $\lim _{x \rightarrow 1} f(x)$(b) $\lim _{x \rightarrow 3} g(x)$(c) $\lim _{x \rightarrow 1} g(f(x))$
Step 1
We substitute $x=1$ into the function to get $f(1)=4-1^{2}=4-1=3$. Therefore, \[ \lim _{x \rightarrow 1} f(x) = 3 \] Show more…
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