Question
Find the limits in Exercises $29-34 .$ Are the functions continuous at the point being approached?$$\lim _{y \rightarrow 1} \sec \left(y \sec ^{2} y-\tan ^{2} y-1\right)$$
Step 1
The secant function is defined as $\sec(x) = \frac{1}{\cos(x)}$ and the tangent function is defined as $\tan(x) = \frac{\sin(x)}{\cos(x)}$. The secant squared function is simply the square of the secant function, i.e., $\sec^2(x) = Show more…
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